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## Homework Statement

A simple harmonic oscillator is displaced 5.00 cm from equilibrium and released at t=0s. Its position at t=1.5 s is 2.00 cm. What is the angular frequency of the oscillator?

The book says the answer is 0.773.

## Homework Equations

F= 1/T = w/ (2*pi)

(theta,f) - (theta, i) = (1/2)(wf+wi)(t)

## The Attempt at a Solution

My thought was to solve for w and use my answer to solve for frequency.

(theta,f) - (theta, i) = (1/2)(wf+wi)(t)

(.02m - .05m) = (1/2)(wf+wi)(1.5)

w =.04 and .04/(2*pi) is not equal to 0.773

thank you for any help