Finding basis of spaces and dimension

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To find a basis for the space of 2x2 matrices A=[a b; c d] where a+d=0, it is established that d must equal -a. The basis can be represented as matrices that span the space, specifically: [1 0; 0 0], [0 1; 0 0], and [0 0; 1 0]. This leads to the conclusion that the dimension of the space is 3, as any matrix in this space can be expressed as a linear combination of the basis elements. Understanding the terms "elements" and "linear sum" is crucial for grasping the concept of vector spaces and their dimensions.
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Homework Statement


Find a basis for each of the spaces and determine its dimension:
The space of all matrices A=[a b, c d] (2x2 matrix) in R^(2x2) such that a+d=0


Homework Equations





The Attempt at a Solution


So I jumped at this question without knowing too much about spaces and dimensions, but:
I think a possible combination of basis can be: [1 0, 0 0]. [0 1, 0 0]. [0 0, 1 0] (not sure if [0 0, 0 -1] would be considered since d would be negative in this case) Also from that I assume the dimension is 3?
Truthfully even if I got it right, I do not even know what happened. Can someone conceptually tell me what I am doing exactly?
Thanks in advance.
 
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you need to come up with a basis, that has elements, such that any 2x2 matrix with a=d can be written as a linear sum of the basis elements.

clearly the basis elements will need to satisfy being a 2x2 matrix with d=a, you first element does not
 
note this is entirely equivalent to considering 4 component vectors in R^4, with x_1 = x_4

often the vector form is easier to conceptualise
 
Last edited:
lanedance said:
you need to come up with a basis, that has elements, such that any 2x2 matrix with a=d can be written as a linear sum of the basis elements.

clearly the basis elements will need to satisfy being a 2x2 matrix with d=a, you first element does not

Can you explain to me how d=a, since a+d=0?
Also since I am actually having a hard time learning this on my own, can you tell me what you mean by "elements" and "linear sum"?
 
maximade said:
Can you explain to me how d=a, since a+d=0?
Also since I am actually having a hard time learning this on my own, can you tell me what you mean by "elements" and "linear sum"?
good pickup, should be a = -d

if you're not familair with those terms, you may need to do a bit of reading.. though i have been a little loose with terminiology

in post #4 i actually meant component and have changed accordingly

a basis, is a set of vectors that spans a vector space

an element is a member of a set, for example a vector in the basis set

a linear combination (or sum) is a vector addition with scalar multiplication
eg. if u,v are vectors, and a,b are scalars, then
w = au + bv is a linear combination

a set, S, of vectors spans a space if any vector in the space can be written as a linear combination of vectors in S
 
From a+ d= 0 you get d=-a as you say. You can then write
\begin{bmatrix}a & b \\ c & d\end{bmatrix}= \begin{bmatrix}a & b \\ c & -a\end{bmatrix}
= \begin{bmatrix}a & 0 \\ 0 & -a\end{bmatrix}+ \begin{bmatrix}0 & b \\ 0 & 0\end{bmatrix}+ \begin{bmatrix}0 & 0 \\ c & 0\end{bmatrix}
and the dimension and a basis should be clear.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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