Finding Center & Radius of Circle C

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Homework Help Overview

The problem involves finding the center and radius of a circle given its equation, specifically x² + y² - 10x + 9 = 0. The subject area is geometry, focusing on the properties of circles and the method of completing the square.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of completing the square to transform the circle's equation into standard form. Some express uncertainty about their attempts and seek clarification on the process.

Discussion Status

There is ongoing exploration of the correct method to complete the square. Some participants have provided partial guidance on the steps needed to rewrite the equation, while others are questioning their own understanding and results.

Contextual Notes

Participants are navigating the complexities of the equation and expressing uncertainty about the completion of the square, indicating a need for further clarification on the method.

thomas49th
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Homework Statement

The circle C, with the centre at the point A, has equation x² + y² - 10x + 9 = 0

Find:

a) the co-ordinates of A,

b) the radius of C

Homework Equations



(x-a)² + (y-b)² = r²

The Attempt at a Solution



... not sure what to do really. any suggestions

thanks :)
 
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Once you do one of these, you'll know how to do them all. Try completing the square for both variables.
 
(x²-5) -16
(y²)+9=0

so does this mean (5,0) is the co-ordinate.
is the radius sqrt(16-9) = sqrt(7)

?

thanks
 
You have a x2 and a y2. How would you get it into the form (x-a)2 and (y-b)2?
 
sorry I am not sure :( did i complete the square correctly?
 
It's sort of only a bit correct. The equation of a circle is [itex](x-x_0)^2 + (y-y_0)^2 = r^2[/itex], where [itex]x_0[/itex] and [itex]y_0[/itex] are the coordinates of the centre and r is the radius.

Complete the square for x^2 - 10x + 9 first, then substitute the resulting expression back into the question, and move the constant to the RHS. You'll get the equation of circle.
 
Thanks! :)
 

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