Finding charge density generating an Electric Field

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The discussion focuses on demonstrating that the electrostatic field E = br is irrotational, confirming that ∇ x E = 0. Participants clarify that to find the charge density ρ(r) generating this electric field, the equation ρ = ε0(div E) applies, leading to ρ = bε0(div r). The divergence of r is debated, with clarification that r represents the vector (x, y, z) rather than a scalar. Ultimately, the conclusion is reached that the divergence can be computed using the vector representation. This understanding is essential for solving the problem accurately.
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Homework Statement



Show that electrostatic field E = br
where b is a constant
is irrotational

Find the charge density ρ(r) which can generate this electric field

Homework Equations



∇ x E = 0 (following stoke theorem)

ρ = ε0(div E) since: div E = \frac{ρ}{ε}

The Attempt at a Solution



The first part (I'm assuming) will suffice as ∇ x E = 0

The second part ρ = ε0(div E) = ε0(div br) = bε0(div r)

The question is whether I can compute (div r) or not. Does "r" in this particular case equal to square root (x+y+z)2? I'm assuming I can't know data given, which is why I am tempted to leave the solution as it is.

Thanks
 
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You cannot take the divergence of a scalar, so I suppose that r is actually the vector:

\vec r=(x,y,z)
 
Ah good, that's what I was thinking. Thanks
 
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