Teptip
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Thanks, solved!
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The discussion revolves around finding the charge on a 4 µF capacitor in an RC circuit with given resistor values. Participants are exploring the relationship between voltage, current, and capacitance in the context of capacitors connected in parallel with resistors.
Some participants have provided calculations and confirmations regarding current and voltage across components. There is an ongoing exploration of the relationship between the voltage across the resistors and the capacitor, with some guidance offered on understanding the connections in the circuit.
Participants are navigating the complexities of circuit analysis involving capacitors and resistors, with some uncertainty about the definitions and relationships between voltage and current in this configuration.
Teptip said:Here is the circuit in question: http://imgur.com/glr2C4f
Homework Statement
Find the charge on the 4 µF capacitor if
R1 = 11 Ω and R2 = 4 Ω .
Answer in units of µC
Homework Equations
V = IR
C = Q/V
The Attempt at a Solution
We've never had to deal with capacitors in parallel with resistors before so I'm not sure how this works.
Do I assume the total resistance of the circuit is in series and thus = 16Ω ?
Teptip said:What voltage do I use for the C=Q/V equation?
Teptip said:Okay so I can calculate current I=V/R = 19/16 = 1.1875 A
No, what do you mean of Vtotal? And you do not need it.Teptip said:V total = (V of Capacitor) + (V of 11Ω Resistor)
You know the voltage across the 11 Ω resistor. Look at the figure. Where are the plates of the capacitor connected to?Teptip said:V of 11Ω Resistor = IR = (1.1875)(11) = 13.0625
Teptip said:Is the voltage I want then just the voltage across the 4Ω resistor?
Teptip said:Ah is it the same current as throughout, since the capacitor is quickly charged?
(I = 1.1875 A so V = (1.1875)(4) and then this voltage is the same that would go through the capacitor?)