Finding critical numbers of function with rational exponent

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To find the critical numbers of the function F(x) = x^(4/5) (x - 4)^(2), the first derivative F'(x) was calculated as (1 / 5th root of x) (x - 4)(2x + 4/5(x-4)). The next step involves determining the values of x that make F'(x) equal to zero, which requires setting each factor of the derivative to zero. The critical values can be found by solving for x in the factors: 1/5th root of x, (x - 4), and (2x + 4/5(x - 4)). This approach will yield the critical numbers necessary for further analysis of the function.
TsAmE
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Homework Statement



Find the critical numbers of the function:

F(x) = x^(4/5) (x - 4)^(2)

Homework Equations



None.

The Attempt at a Solution



I differentiated and got to (1 / 5th root of x) (x - 4)(2x + 4/5(x-4))

but I don't know how I can simplify the expression to be able to solve for the critical values of x
 
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TsAmE said:

Homework Statement



Find the critical numbers of the function:

F(x) = x^(4/5) (x - 4)^(2)

Homework Equations



None.

The Attempt at a Solution



I differentiated and got to (1 / 5th root of x) (x - 4)(2x + 4/5(x-4))

but I don't know how I can simplify the expression to be able to solve for the critical values of x
You're almost there. What values of x make F'(x) = 0? You have three factors, so for F'(x) to be zero, at least one of the factors must be zero.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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