Finding Curvature of Vector Function

  • Thread starter Thread starter Bashyboy
  • Start date Start date
  • Tags Tags
    Curvature
Click For Summary
To find the curvature K of the curve defined by the vector function r(t) = ⟨2 cos t, 2 sin t, t⟩, the arc length function s(t) must be determined using the integral s(t) = ∫_a^t ||r'(u)|| du. The choice of the lower limit 'a' for the integral is flexible, as selecting a value that ensures s(0) = 0 is common but not mandatory; it can be any point along the curve. This flexibility is due to the fact that the specific starting point does not affect the final curvature calculation, as 'a' will cancel out in the process. Understanding this concept is crucial for correctly applying the Frenet-Serret formulas to determine curvature without needing extensive integration.
Bashyboy
Messages
1,419
Reaction score
5

Homework Statement


Find the curvature K of the curve, where s is the arc length parameter:

\vec{r}(t) = \langle 2 \cos t , 2 \sin t, t \rangle

Homework Equations



s(t) = \int_a ^t ||\vec{r}'(u)||du

The Attempt at a Solution



I know I need to find the arc length function, in order to find the curvature function; however, I am unsure as to what I should choose a to be for the lower limit of the integral.
 
Last edited:
Physics news on Phys.org
You need to use the Frenet-Serret formulae and the chain rule.

You should not need to perform any integrations.
 
Last edited:
Bashyboy said:

Homework Statement


Find the curvature K of the curve, where s is the arc length parameter:

\vec{r}(t) = \langle 2 \cos t , 2 \sin t, t \rangle




Homework Equations



s(t) = \int_a ^t ||\vec{r}'(u)||du

The Attempt at a Solution



I know I need to find the arc length function, in order to find the curvature function; however, I am unsure as to what I should choose a to be for the lower limit of the integral.

Choose it so that s(0)=0.
 
So, the choice is arbitrary? If so, why?
 
Bashyboy said:
So, the choice is arbitrary? If so, why?

Why not? Just as you can start time at any instant, you can measure an arc length from any point on a line. Usually the arc length is connected to the trajectory of an object if time is involved, that is why I suggested s(0)=0. But you also can keep "a" in the expression s(t). Solve the problem and you will see that"a" cancels.

ehild
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K