Finding deBroigle wavelength of a charged electron

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ParrotPete
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Homework Statement


Given an electron with total energy 1 KeV, determine it's deBroigle wavelength.


Homework Equations



E^2 = (mc^2)^2+(pc)^2
[tex]\lambda[/tex] = [tex]\frac{h}{p}[/tex]


The Attempt at a Solution



(pc)^2 = E^2 - (mc^2)^2 <> p = ± [tex]\frac{1}{c}[/tex] [tex]\sqrt{E^2-(mc^2)^2}[/tex]

What am I doing wrong?
When I plug in E = 10^3 eV and (mc^2) = 0.511 * 10^6 eV I get an imaginary result.
 
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ParrotPete said:

Homework Statement


Given an electron with total energy 1 KeV, determine it's deBroigle wavelength.


Homework Equations



E^2 = (mc^2)^2+(pc)^2
[tex]\lambda[/tex] = [tex]\frac{h}{p}[/tex]


The Attempt at a Solution



(pc)^2 = E^2 - (mc^2)^2 <> p = ± [tex]\frac{1}{c}[/tex] [tex]\sqrt{E^2-(mc^2)^2}[/tex]

What am I doing wrong?
When I plug in E = 10^3 eV and (mc^2) = 0.511 * 10^6 eV I get an imaginary result.

I think the question is written incorrectly and that the 1 KeV is the kinetic energy of the electron and not its total energy.