Finding Distribution Function for p(x) = log_10(1 + 1/x)

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SUMMARY

The discussion focuses on finding the distribution function for the discrete probability function defined as p(x) = log_10(1 + 1/x) for x = 1, 2, 3, ..., 9, with p(x) = 0 otherwise. The user successfully proved that p(x) is a probability function by demonstrating that the sum of all values equals 1. To derive the distribution function, it is established that the cumulative distribution function (CDF) is the sum of probabilities for all outcomes less than or equal to x, specifically P(X ≤ x) = Σ p(y) for y = 1 to x.

PREREQUISITES
  • Understanding of discrete probability functions
  • Familiarity with cumulative distribution functions (CDF)
  • Knowledge of logarithmic functions, specifically log_10
  • Basic algebra for summation and inequalities
NEXT STEPS
  • Study the properties of cumulative distribution functions (CDF)
  • Learn how to derive CDFs from discrete probability mass functions (PMF)
  • Explore examples of discrete distributions, such as binomial and Poisson distributions
  • Review the concept of inequalities in probability theory
USEFUL FOR

Students studying probability theory, particularly those working on discrete random variables and distribution functions, as well as educators seeking to clarify concepts related to probability distributions.

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Homework Statement


I have the following question

p(x) = log_10(1 + 1/x) for x = 1,2,3, ... 9 (otherwise p(x)=0)

So firstly I had to prove that p(x) is a probability function, which I have done so (by proving the sum of all the values =1)
anyway the second thing I have to do is determine an expression for the corresponding distribution function. How exactly do I do this? The information on wiki is confusing and the textbook doesn't seem to cover it? Can anyone help?


Homework Equations





The Attempt at a Solution




I've read 2 textbooks and the internet and I can't find an exact method or style of answer, but I know it has to have inequalities in it and I have done some working out plugging in each value and getting an answer, but I am unable to write it out in the format that the textbook has... that is would be something like

P_x(x) = { 0 for x <1
... etc... but if I wrote something like =1 for x<=9 that isn't exactly true because if x was 8.5 then it wouldn't equal one... this is what I was just working on when I realized I must have the wrong idea... the question asks me to write an expression for the distribution function... is there a simple way I can just write a general?? Do I need to interal because I have worked that out just in case...

Thanks for any help you can give me..
 
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What you're working with here is a discrete probability function, as you probably know. For each x you get the probability for that outcome. The random variable presumably denoted X has for example a chance log10(1 + 1/1) = log10(2) of being 1, and so on for the other defined values of x.

A distribution function, on the other hand, doesn't give you the probability that X is equal to x, but the probability that the outcome of X is less than or equal, to the given x. In this case, it's just the sum of all p(y) where 1 <= y <= x.
 

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