Finding domain for when composite function is continuous

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The function h(x) = ln{x^2} is continuous for all x except at x = 0, where it is neither defined nor continuous. The natural logarithm is only defined for positive arguments, which implies x^2 must be greater than 0, leading to the conclusion that x cannot equal 0. To prove continuity, one can show that the function is differentiable for x ≠ 0, which implies continuity. Additionally, it's important to note that the correct notation for the natural logarithm is ln, not In. The discussion emphasizes understanding the domain and continuity of composite functions in relation to logarithmic properties.
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Homework Statement
Please see below
Relevant Equations
Please see below
I am trying to find where ##h(x) =In{x^2}## is continuous on it's entire domain.

My reasoning is since natural log is defined for ##x > 0##, then the argument ##x^2## should be positive, ##x^2 > 0##, we can see without solving this equation that ##x ≠ 0## for this equation to be true, however, does someone please know how we could prove this by solving that equation for x?

My working is
##x > 0## (Taking square root of both sides of the equation)

Many thanks!
 
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ChiralSuperfields said:
Homework Statement: Please see below
Relevant Equations: Please see below

I am trying to find where ##h(x) =In{x^2}## is continuous on it's entire domain.

My reasoning is since natural log is defined for ##x > 0##, then the argument ##x^2## should be positive, ##x^2 > 0##, we can see without solving this equation that ##x ≠ 0## for this equation to be true, however, does someone please know how we could prove this by solving that equation for x?

My working is
##x > 0## (Taking square root of both sides of the equation)

Many thanks!
It is neither defined nor continuous at ##x=0.## It is continuous everywhere else. What do you use to prove continuity? E.g. it is differentiable at ##x\neq 0## and therewith continuous. Or you use a definition for continuity. There are a few, so which one do you use?
 
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ChiralSuperfields said:
I am trying to find where ##h(x) =In{x^2}## is continuous on it's entire domain.
There is no "##In()## function; i.e., starting with uppercase i. It's ##\ln()##, with a lowercase letter l (ell), short for logarithmus naturalis.
 
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Note that \ln x^2 = 2\ln |x|.
 
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