Finding dx & dy: Solving Math Homework Problem

  • Thread starter Thread starter renlok
  • Start date Start date
  • Tags Tags
    Dx
Click For Summary

Homework Help Overview

The discussion revolves around finding the infinitesimal changes, δx and δy, for the equations x = (1/2)(u^2 - v^2) and y = uv, with respect to the variables u and v.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore methods for determining δx and δy, with some suggesting the use of partial derivatives while others question the need for gradients. There is a discussion on treating variables as constants in the context of differentiation.

Discussion Status

The conversation is ongoing, with participants providing different perspectives on how to approach the problem. Some guidance has been offered regarding the treatment of variables, but no consensus has been reached on the method to find δx.

Contextual Notes

There is a noted confusion regarding the interpretation of the problem, particularly whether to treat u and v as independent variables or as functions of another variable. This has led to differing approaches in the discussion.

renlok
Messages
12
Reaction score
0

Homework Statement


x = (1/2)(u^2 - v^2), y = uv
find \delta{x} and \delta{y}

Homework Equations


-

The Attempt at a Solution


I think its simple enough but I don't know what sort of method to use to answer this.

Any help would be really awesome :)
 
Last edited:
Physics news on Phys.org
With respect to what are you finding the partial derivatives - u or v?

In either case, treat the other variable as a constant. If with respect to u, then treat v as a constant. If with respect to v, then treat u as a constant.
 
not in respect to something i don't need to find a gradient, i need to find the infintesimal change in x or y in terms of v & u.

I've found for finding \delta{y} if you can treat v & u as functions of x you can just use the product rule and divide though by \delta{x} to leave you with \delta{y} = u\delta{v} + v\delta{u}
but I've still no clue how to get \delta{x}
 
I'm not sure what you did to find δy. What you said doesn't really make sense. Think of x and y as functions of u and v:

x = x(u,v)
y = y(u,v)

Then you have

\begin{align*}<br /> dx &amp; = \frac{\partial x}{\partial u} du + \frac{\partial x}{\partial v} dv \\<br /> dy &amp; = \frac{\partial y}{\partial u} du + \frac{\partial y}{\partial v} dv<br /> \end{align*}<br />
 

Similar threads

Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
48
Views
4K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K