Finding dy/dt with equation and dy/dx

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SUMMARY

The discussion centers on finding dy/dt using implicit differentiation for the equation tan(y) + x^3 = y^2 + 1, with dx/dt = -2 at the point (1,0). The correct approach involves differentiating both sides with respect to t, resulting in the equation sec^2(y) (dy/dt) + 3x^2 (dx/dt) = 2y (dy/dt). By substituting the known values into this equation, one can solve for dy/dt definitively.

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Homework Statement


If tan y + (x^3) = (y^2) + 1, and dx/dt = -2, what is the value of dy/dt at the point (1,0)?



Homework Equations


See above.


The Attempt at a Solution


I know I can't plug in my points until I get the equation... Do I just use implicit differentiation, then whenever I have a dx/dt plug in -2, and solve for the dy/dt? Or do I have to do something totally different?
 
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Yes, differentiating with respect to t gives
[tex]sec^2(y) (dy/dt)+ 3x^2 (dx/dt)= 2y (dy/dt)[/tex]

Put in the given values and solve for dy/dt.
 
That's what I thought! Thanks!
 

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