Finding Electric Field in Spherical Hole

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SUMMARY

The discussion centers on calculating the electric field strength (E) inside a spherical hole located within a uniformly charged sphere with charge density ρ. The user initially considers using Gauss's law but is advised to apply the superposition principle instead. Specifically, the correct approach involves conceptualizing the hole as a region of negative charge density (-ρ) within the positive charge density (ρ) of the larger sphere, allowing for a clearer understanding of the forces at play within the hole.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric field concepts and charge density
  • Knowledge of the superposition principle in physics
  • Basic calculus for integration in three dimensions
NEXT STEPS
  • Study the application of Gauss's Law for spherical symmetry
  • Explore the superposition principle in electrostatics
  • Learn about electric field calculations in non-uniform charge distributions
  • Investigate the effects of charge density variations on electric fields
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electrostatics, particularly those studying electric fields in charged systems.

du_uk
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Homework Statement


A spherical hole is located inside a uniformly charged sphere of charge density p. The centre of the hole is at a distance a from the centre of the sphere, and the radii of the sphere and the hole are given by R and R' respectively. Determine the electric field strength E inside the hole.

Homework Equations





The Attempt at a Solution


I think I need to use Gauss's law the find the electric field around this red surface:
http://img20.imageshack.us/img20/6870/electroqy.jpg
and since there is symmetry, integrate around 0 to 2(pi) wrt the extra (third dimensional) coordinate.
Then minus the electric field for a sphere outside the charge.

Am I going about this the right way?

Thanks
 
Last edited by a moderator:
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Hi du_uk, welcome to PF!:smile:

du_uk said:
I think I need to use Gauss's law the find the electric field around this red surface:
http://img20.imageshack.us/img20/6870/electroqy.jpg
and since there is symmetry, integrate around 0 to 2(pi) wrt the extra (third dimensional) coordinate.
Then minus the electric field for a sphere outside the charge.

Am I going about this the right way?

I'm not sure exactly what you mean here, but no, you are not going in the right direction. What exactly is the symmetry you are referring to here?

Instead, take advantage of the superposition principle...what happens if you place an object of charge density [itex]-\rho[/itex] inside a larger object of charge density [itex]+\rho[/itex]?:wink:
 
Last edited by a moderator:
More to the point, place a spherical charge density [itex]-\rho[/itex] inside a larger spherical charge density [itex]+\rho[/itex]. What are the forces inside the smaller sphere?
 

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