Finding electric potential using charge density

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SUMMARY

The electric potential of a 5 cm radius conducting sphere with a surface charge density of 2x10^-6 C/m² is calculated using the formula V = K(q/r). The solution yields an electric potential of 1.12 x 10^4 V, confirming that the calculation is straightforward and accurate. There are no additional complexities in this scenario, as the method applied is correct and sufficient for the problem at hand.

PREREQUISITES
  • Understanding of electric potential and charge density concepts
  • Familiarity with the formula V = K(q/r) for calculating electric potential
  • Knowledge of the constant K (Coulomb's constant) and its value
  • Basic principles of electrostatics and conductors
NEXT STEPS
  • Review the principles of electrostatics and the behavior of conductors in electric fields
  • Explore the derivation and applications of Coulomb's law in electric potential calculations
  • Learn about the implications of charge distribution on electric potential in different geometries
  • Investigate the relationship between electric potential and electric field strength
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric potential calculations in conductive materials.

AMMax
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Homework Statement



a 5 cm radius conducting sphere has a charge density of 2x10^-6 C/m^2 on its surface. Its electric potential, relative to the potential far away is?

Homework Equations



I used V= K(q/r)

The Attempt at a Solution



Using the above equation I got 1.12 x 10^4. This seems too easy. I think I am missing something here.
 
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You are not missing anything. It is that easy.
 

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