Finding end temperature of mixed substances

  • Thread starter dthmnstr
  • Start date
  • #1
7
0
hi im having a bit of a problem with this anybody care to help me out?

a calorimeter contains 0.761kg of water. both calorimeter and water have the temperature 4 degrees celsius. 0.054kg of liquid glycerol at 26 degrees celsius is then poured into the calorimeter. find the end temperature of the entire mixture.

C(calorimeter)=86J/kgK C(water)=4180J/kgK C(glycerol)=2430J/kgK


so far i've tried the equations Q(calorimeter)+Q(water)=Q(glyserol) and Q(calorimeter)+Q(water)=Q(glycerol)+Q(glycerol turning solid) but i always get some kind of brutal answer, i think the answer lies somewhere between 10 'c and 20 'c but im unsure of how to formulate the equation.
 

Answers and Replies

  • #2
648
2
Use the first equation you tried.
Let the temperature of the final mixture be, t, for example.
Find the energy gained by the water in rising to that temperature from 4 degrees.
Find the energy gained by the calorimeter in rising to that temperature from 4 degrees
Find the energy lost by the glycerol in falling to that temperature from 26 degrees
Use conservation of energy. Energy gained by Water and calorimeter = energy lost by glycerol. (Assuming no loss to surroundings) Solve for t.
 
Last edited:
  • #3
9
0
hi im having a bit of a problem with this anybody care to help me out?

a calorimeter contains 0.761kg of water. both calorimeter and water have the temperature 4 degrees celsius. 0.054kg of liquid glycerol at 26 degrees celsius is then poured into the calorimeter. find the end temperature of the entire mixture.

C(calorimeter)=86J/kgK C(water)=4180J/kgK C(glycerol)=2430J/kgK


so far i've tried the equations Q(calorimeter)+Q(water)=Q(glyserol) and Q(calorimeter)+Q(water)=Q(glycerol)+Q(glycerol turning solid) but i always get some kind of brutal answer, i think the answer lies somewhere between 10 'c and 20 'c but im unsure of how to formulate the equation.

Did you remember to convert to kelvin?
 
  • #4
7
0
thanks dudes for the help, i just messed up with placing the T in the equation so i got it solved properly now
 

Related Threads on Finding end temperature of mixed substances

Replies
16
Views
7K
Replies
24
Views
13K
Replies
10
Views
4K
Replies
2
Views
3K
Replies
26
Views
29K
Replies
9
Views
3K
Replies
6
Views
3K
Replies
2
Views
8K
Top