Finding Equation of Motion for Oscillations Using Lagrangian Methods

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SUMMARY

The discussion focuses on deriving the equation of motion for a rigid straight uniform bar attached to a wall and supported by a spring, using Lagrangian methods. The angular frequency of the oscillation is established as ω = (a/L) * √(3k/m), where 'a' is the distance from the hinge to the spring, 'L' is the length of the bar, 'k' is the spring constant, and 'm' is the mass of the bar. The inertia of the rod is confirmed as I = (1/3)ML², and the Lagrangian is defined as L = K - V, with K representing kinetic energy and V representing potential energy. The user successfully solved the problem after initial confusion regarding the application of Lagrangian mechanics.

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  • Understanding of Lagrangian mechanics
  • Familiarity with oscillatory motion
  • Knowledge of kinetic and potential energy equations
  • Basic concepts of rotational inertia
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  • Study the derivation of Lagrangian equations in classical mechanics
  • Explore the concept of angular frequency in oscillatory systems
  • Learn about the applications of the spring constant in mechanical systems
  • Investigate the role of rotational inertia in dynamics
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Physics students, mechanical engineers, and anyone interested in advanced mechanics, particularly those studying oscillations and Lagrangian methods.

James1991
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1. A rigid straight uniform bar of mass m and length l is attached by a frictionless hinge
at one end to a fixed wall so that it can move in a vertical plane. At a distance a from
the hinge it is supported by a spring of stiffness constant k, as shown in the figure

Ignoring gravitational effects, make use of Lagrangian methods to find the equation of
motion for small oscillations about the position of equilibrium (in which the bar is
horizontal) and show that the angular frequency of the motion is

\omega = a/L * \sqrt{}3k/m

Where a is the length from the wall to the spring along the rod and L is the length of the rod

Homework Equations


F=-kx
U=1/2kx^2
I = 1/3ML^2

The Attempt at a Solution


Right so i think the inertia of the rod is 1/3ML^2
and i tried to set up the lagrangian
as L = K - V
where K = M\omega^2{}theta*x^2
and V = 1/2kx^2

and i did d/dt(dL/dthetaDOT) = dL/dtheta
but it didnt work at all tbh, maybe i don't need to do it via this method, either way I'm abit lost as to what to do next and I've spent ages on it now.
Any help would be greatly appreciated
:)
 
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You forgot to attach the figure.
Where did you get this question from?
Do you mind telling what course you are pursuing?
 


It's from a Lagrangian Mechanics module I'm doing. I'm studying Physics.
I managed to do the question in the end :)
 

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