Finding equivalent resistance with parallel resistors in a mixed circuit

[dewdrop714]

1. The problem statement

http://s685.photobucket.com/albums/vv212/dewdr0p714/?action=view&current=3circuitontakehometest1.jpg

The voltage is on the left (100V) and the jagged lines are the resistors in Ohms. I need to find the equivalent resistance of the circuit and after that the current flowing through the 4 ohm resistor.

2. Homework Equations

I = V/R


3. The Attempt at a Solution

I'm not sure if I calculated these correctly...

Equiv Resistance = 7 + (10/2) + 8 + (4/2) + 3 = 25 Ohms.

For the current flowing through the 8 ohm resistor, I = V/R = 100V/25ohms = 4 Amps

 

[tiny-tim]

Welcome to PF!

Hi dewdrop714! Welcome to PF!

The voltage is on the left (100V) and the jagged lines are the resistors in Ohms. I need to find the equivalent resistance of the circuit and after that the current flowing through the 4 ohm resistor.
…
Equiv Resistance = 7 + (10/2) + 8 + (4/2) + 3 = 25 Ohms.

Looks good!

For the current flowing through the 8 ohm resistor, I = V/R = 100V/25ohms = 4 Amps

8 ohm?

Anyway, that's the current through the whole circuit … you need the current flowing through just the bit of wire containing the 4(?) ohm resistor.