Finding Force with friction on a slope

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Homework Help Overview

The discussion revolves around the correct representation of forces and angles in a free body diagram involving friction on a slope. Participants are examining the placement of the angle Φ and the orientation of the normal force in relation to the surface.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the correct positioning of the angle Φ in relation to the force vector and the vertical direction. Questions arise regarding the accuracy of the free body diagram and the implications of the angle's placement on the understanding of the forces involved.

Discussion Status

There is an ongoing exchange of feedback regarding the representation of angles in the diagram. Some participants have provided guidance on correcting the angle's placement, while others express uncertainty about the vector orientations. The discussion reflects a collaborative effort to refine the understanding of the problem without reaching a definitive conclusion.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the amount of information they can share or the methods they can use to resolve the problem.

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image.jpg
1. Homework Statement

I was wondering if my phi angle was in the right position from the picture. Also, it is correct that my normal force FN is perpendicular to the surface?

Homework Equations


Newton's second law
fk=ukFN[/B]

The Attempt at a Solution


Refer to picture[/B]
 
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The angle Φ is not correctly indicated in your diagram. Note that Φ is the angle F makes to the vertical direction. Your normal force is correctly drawn.
 
So the angle would just be on the other side of that Force vector
 
I'm not sure exactly what you mean. Could you be more specific or attach another figure?
 
image.jpg
 
That's still not quite right. You now have Φ as the angle between F and your y axis. But Φ is the angle between F and the vertical direction.
 
I get what you are saying about the vertical direction, but I just don't get how that vector wouldn't be in that quadrant
 
You have F in the correct quadrant of your x-y coordinate system. But you do not have the angle Φ indicated correctly. Φ is not the angle between F and the y axis. Φ is the angle between F and the vertical direction. The vertical direction is along the same line that mg acts. Draw a dotted line along mg and extend it upward into the same quadrant that F is in.
 
image.jpg
 
  • #10
You rotated F to the wrong side of the vertical. In the original figure, F points up and to the left. You now have F pointing up and to the right.
 
  • #11
image.jpg

Hopefully this is correct. Sorry to put you through all of that. I just struggle with these type of angle concepts
 
  • #12
Yes, your free body diagram is now correct. You just need to find the angle that F makes to the x-axis (or y axis).
 
  • #13
Thank you for all your help
 

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