Finding Friction: Check My Work for Mistakes

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SUMMARY

The discussion centers on calculating the coefficient of kinetic friction for a 37 kg box sliding down a 35-degree ramp with an acceleration of 1.35 m/s². The user calculated the gravitational force (Fg) as 362.97 N and derived the normal force (Fn) as 297.33 N. However, the calculated coefficient of kinetic friction (μ) was incorrectly stated as 0.168, which is less than 1, raising concerns about the accuracy of the calculations. The correct approach involves ensuring that the frictional force is derived from the net force acting on the box.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational force components (Fg)
  • Familiarity with the concept of normal force (Fn)
  • Basic understanding of frictional forces and coefficients (Ff = μFn)
NEXT STEPS
  • Review the derivation of gravitational force components in inclined planes.
  • Study the relationship between net force, mass, and acceleration in dynamics.
  • Learn how to accurately calculate the coefficient of kinetic friction using experimental data.
  • Explore the implications of coefficients of friction greater than one in practical scenarios.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and friction, as well as educators seeking to clarify concepts related to forces on inclined planes.

missashley
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Homework Statement



A 37 kg box slides down a 35 degree ramp with an acceleration of 1.35 m/s^2. The acceleration of gravity is 9.81 m/s^2.

Find the coefficient of kinetic friction between the box and the ramp.


Homework Equations



Ff= MkFn
Finding X and Y components of Fg

The Attempt at a Solution



Fg = 37 * 9.81 = 362.97 N
Fgx = 362.97 sin 35 = 208.1910391
Fgy = 362.97 cos 35 = 297.3276175

Fn = Fgy

F = ma
F = 37 * 1.35 = 49.95

49.95 / 297.3276175 = 0.167996 <~coefficient of kinetic friction

Did I do this right? What did I do wrong?


I think I did something wrong because the coefficient is greater than one

Please check what I did wrong and how can I fix it?
 
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missashley said:
49.95 / 297.3276175 = 0.167996 <~coefficient of kinetic friction

This is wrong. You can find the frictional force from known data and
[tex]\mu[/tex] = F[tex]_{fric}[/tex] / F[tex]_{normal}[/tex]
 

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