# Finding general solution for object falling in air

1. Mar 5, 2010

### andrey21

1. Using separation of variables show that:
v' = (cd/M)(v^2) - g has a general solution of:

v = 20SQRT10 x ((1+Ae^(t/SQRT10)/(1-Ae^(t/SQRT10))

2. Relevant equations

3. The attempt at a solution
Have attempted numerous times with little success help appreciated!

2. Mar 5, 2010

### rock.freak667

Divide both sides by

$$\frac{cd}{M}v^2 - g$$

3. Mar 5, 2010

### andrey21

Just come to the correct answer and now is asking to find the terminal velocity. How would I go about doing that?

4. Mar 5, 2010

### rock.freak667

That would be where the rate of change or velocity is zero.

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