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Finding general solution for object falling in air

  1. Mar 5, 2010 #1
    1. Using separation of variables show that:
    v' = (cd/M)(v^2) - g has a general solution of:

    v = 20SQRT10 x ((1+Ae^(t/SQRT10)/(1-Ae^(t/SQRT10))



    2. Relevant equations



    3. The attempt at a solution
    Have attempted numerous times with little success help appreciated!
     
  2. jcsd
  3. Mar 5, 2010 #2

    rock.freak667

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    Divide both sides by


    [tex]\frac{cd}{M}v^2 - g [/tex]
     
  4. Mar 5, 2010 #3
    Just come to the correct answer and now is asking to find the terminal velocity. How would I go about doing that?
     
  5. Mar 5, 2010 #4

    rock.freak667

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    That would be where the rate of change or velocity is zero.
     
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