Finding Greatest, Least, Maximal & Minimal Elements for "Divides" Relation

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SUMMARY

The discussion focuses on finding the greatest, least, maximal, and minimal elements for the "divides" relation on the set A = {2, 3, 4, 6, 8, 9, 12, 18}. The "divides" relation is defined such that a divides b if b = ka for some integer k. Participants clarify how to construct a Hasse diagram for the set, illustrating the relationships between the numbers based on divisibility. Key insights include identifying that 18 is divisible by 2, 3, 6, and 9, while 12 is divisible by 2, 3, 4, and 6, and understanding the transitive property in constructing the diagram.

PREREQUISITES
  • Understanding of the "divides" relation in mathematics
  • Familiarity with Hasse diagrams
  • Basic knowledge of integer arithmetic
  • Concept of transitivity in relations
NEXT STEPS
  • Study how to construct Hasse diagrams for different sets
  • Learn about the properties of divisibility in number theory
  • Explore the concept of maximal and minimal elements in partially ordered sets
  • Investigate the transitive property and its applications in relations
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Mathematicians, educators, and students studying number theory or discrete mathematics, particularly those interested in relations and order theory.

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confused on the "divides" relation, find all greatest, least, maximal, minal elememen

Hello everyone I'm not sure how I'm suppose to do this...

The problem is the following:
Find all greatest, least, maximal, minimal elemnts for the relations.

It says to find that on exercise 16b. I looked at 16b. and it says:

Consider the "divides" relation on each of the following sets A. Draw the Hasse diagram for each relation.

b. A = {2,3,4, 6, 8, 9, 12, 18}

Well i looked up divides relation and its defined as the following:

a|b if and only if b = ka for some integer k.

Im not sure how figure anything out with that definition but maybe I'm missing somthing.

in part a of this problem, htey found the following hasse diagram if this helps any:
A = {1,2,4,5,10,15,20}
20
4 10 15
2 5
1

20 connects to 4 and 10
4 connects to 2, 2 connects to 1
10 connects to 5 and 5 connects to 15 and 1

i have no idea how they got this either, any explanation would be great!
 
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I would think that anyone who can do arithmetic would know about "divides"! "a divides b" if and only if b/a is an integer.

It was "Hasse diagram" you should have defined! I had to look that up. A Hasse diagram of a set of numbers has the largest number at the top, smaller numbers below with lines going downward from the large numbers to those smaller numbers that divide it.

The numbers are {2,3,4, 6, 8, 9, 12, 18}. 18= (2)(9)= 3(6) so 2, 3, 6, and 9 all divide 18 and there should be lines from them to 18. 12= (4)(3)= 2(6) so there should be lines from 2, 3, 4, and 6 to 12. 9= (3)(3) so there should be a line from 3 to 9. 8= (2)(4) so there should be lines from 2 and 4 to 8. 6= (2)(3) so there should be lines from 2 and 3 to 6. 4= (2)(2) so there should be a line from 2 to 4.
 
Thanks again Ivy, I got the hang of the diagram after awhile. The transitivity property kicks in so you don;'t have to draw all the lines to 12 if there is already a "node" connecting to it.
 

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