Finding height of a well using speed of sound

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Homework Help Overview

The problem involves determining the height of a well based on the time it takes for a coin to fall and the sound of the splash to travel back up. The scenario assumes a speed of sound of 343 m/s and neglects air resistance, with gravitational acceleration given as 9.8 m/s².

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss breaking down the total time into two components: the time for the coin to fall and the time for the sound to travel back up. There is mention of using kinematic relationships to relate distance to time instead of speed.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem by suggesting the separation of the time components. There is an emphasis on the original poster needing to derive equations independently, indicating a focus on the learning process.

Contextual Notes

Participants note the challenge of determining the time taken for the sound to reach the observer, which is a key aspect of the problem. There is a recognition of the need for the original poster to engage deeply with the equations involved.

barge56
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Homework Statement


The problem is you drop a coin into a well then 3 second later you hear the splash. With this information find out the height of the well.

Assume 343 m/s is the speed of sound and neglect any effects due to air resistance.

g = acceleration due to gravity = 9.8 m/s^2
v0 = initial velocity = 0 m/s
v1 = final velocity
H = height
t1 = initial time = 0 s
t2 = time at final velocity

Homework Equations


H = (v0^2 - v1^2)/2g

v1 = v0 - g(t2 - t1)


The Attempt at a Solution


Reduced equation to H = v0^2/2g and found v0 to be -9.8m/s^2(3s - 343m/s(t2))

I'm mainly having trouble trying to find out how much time was taken off for the sound of the splash reaching you.

Any help is appreciated.

 
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barge56 said:

The Attempt at a Solution


Reduced equation to H = v0^2/2g and found v0 to be -9.8m/s^2(3s - 343m/s(t2))
Instead of trying to relate distance to speed, which you have no information about, relate distance to time. Use a different kinematic relationship.

I'm mainly having trouble trying to find out how much time was taken off for the sound of the splash reaching you.
Think of the total time as having two parts:
(1) The time it takes for the coin to reach the water
(2) The time it takes for the sound to go from the water to the top of the well

For the second time, realize that sound travels at a constant speed.
 
The coin falls down to the bottom of the well in time t_1. The sound travels up, at velocity s, to your ear in time t_2. Now we can write 3 basic equations.

<< equations deleted by berkeman >>

We have three unknowns and threee equations, that means that we can solve and figure out h.
 
Last edited by a moderator:
Jebus_Chris said:
The coin falls down to the bottom of the well in time t_1. The sound travels up, at velocity s, to your ear in time t_2. Now we can write 3 basic equations.

<< equations deleted by berkeman >>

We have three unknowns and threee equations, that means that we can solve and figure out h.

Please let the OP figure out those equations on their own. They must do the bulk of the work on their homework/coursework problems.
 

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