Finding height of image for a concave mirror

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SUMMARY

To determine the height of an image (hi) for a concave mirror, the magnification equation m = -di/do = hi/ho is essential. The focal length (f), object distance (do), and image distance (di) are provided, but the height of the object (ho) is necessary to calculate hi. Without knowing ho, it is impossible to derive hi, as the relationship between these variables is fixed and cannot be manipulated arbitrarily. Thus, both the object height and the distances must be known to solve for the image height.

PREREQUISITES
  • Understanding of concave mirror properties
  • Familiarity with the magnification equation
  • Knowledge of focal length and its significance
  • Basic grasp of object and image distances in optics
NEXT STEPS
  • Study the derivation of the mirror formula for concave mirrors
  • Learn about the relationship between object height and image height in optics
  • Explore practical applications of concave mirrors in real-world scenarios
  • Investigate the effects of varying object distances on image formation
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding image formation in concave mirrors.

chester89
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Ok, there's something I just don't understand. I know that to find the height of an image (hi), you need to use the magnification equation m = -di/do = hi/ho. And for this question, the focal length (f), distance of object (do), and distance of image (di) are given. Now, if I want to find the height of the image (hi), I would need the height of the object (ho) to finish the equation, but I don't, so now I'm stumpted on what to do with this question.

I know 'hi = -diho/do' is the equation but if I don't have ho, than how can I find hi.

Any help would be greatly appreciated.
 
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Edited, misinterpretation.

I don't believe you can find the height of the image without the height of the object. The focal length and a given object distance will determind the image distance. No other focused distance is possible. We cannot arbitrarily choose some image distance.
 
Last edited:

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