Finding how long it takes given changing acceleration

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SUMMARY

The discussion focuses on calculating the time required for an automobile to accelerate from 72.0 km/hr to 100.0 km/hr given a constant acceleration of 1.57 m/s². The relevant kinematic equation used is vf = vi + at, where vf is the final velocity, vi is the initial velocity, and a is the acceleration. The correct conversion of units is crucial, as 72.0 km/hr converts to 20.0 m/s and 100.0 km/hr converts to 27.78 m/s. The final calculation shows that the time taken to accelerate is approximately 17.83 seconds.

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  • Understanding of kinematic equations, specifically vf = vi + at
  • Ability to convert units between kilometers per hour and meters per second
  • Familiarity with acceleration concepts in physics
  • Basic algebra skills for solving equations
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  • Learn unit conversion techniques between km/hr and m/s
  • Study the derivation and application of kinematic equations
  • Explore real-world applications of acceleration in automotive physics
  • Investigate the effects of varying acceleration on time calculations
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Students studying physics, particularly those focusing on kinematics, as well as automotive engineers and enthusiasts interested in vehicle performance metrics.

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Homework Statement


At highway speeds, a particular automobile is capable of an acceleration of about 1.57 m/s2. At this rate, how long does it take to accelerate from 72.0 km/hr to 100.0 km/hr?


Homework Equations



I was given: vf = vi + at

The Attempt at a Solution



Simplifying the velocities I got 28 = 1.57a
and a= 17.83 s.
 
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lim said:

Homework Statement


At highway speeds, a particular automobile is capable of an acceleration of about 1.57 m/s2. At this rate, how long does it take to accelerate from 72.0 km/hr to 100.0 km/hr?


Homework Equations



I was given: vf = vi + at

The Attempt at a Solution



Simplifying the velocities I got 28 = 1.57a
and a= 17.83 s.

careful about units... convert km/hr to m/s or convert m/s^2 to km/hr^2...
 

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