Finding impedance of rlc parallel ckt

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SUMMARY

The impedance of a parallel RLC circuit is calculated by first determining the individual admittance of each component and then summing these values before taking the reciprocal to find the total impedance. This method is essential as it ensures accuracy, particularly when dealing with complex impedances. The discussion highlights that using the admittance approach yields consistent results compared to directly calculating impedance using the parallel resistance formula. The mathematical relationship is defined as 1/((1/Z1) + (1/Z2) + (1/Z3)) = Zt, where Zt represents the total impedance.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with complex impedance
  • Knowledge of admittance and its calculation
  • Basic algebra for circuit analysis
NEXT STEPS
  • Study the derivation of admittance in parallel RLC circuits
  • Learn about complex impedance calculations in AC circuits
  • Explore the application of the formula Z1||Z2 = (Z1*Z2)/(Z1+Z2)
  • Investigate common errors in impedance calculations
USEFUL FOR

Electrical engineers, circuit designers, and students studying RLC circuits will benefit from this discussion, particularly those looking to deepen their understanding of impedance calculations in parallel configurations.

umed9
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in most of the books i have seen that while finding an impedance for an parallel RLC circuit first they find the individual admittance of each of the element the after summation of these they take reciprocal to find the impedance
why is it done like that can't we find the impedance in a normal way of finding resistance in parallel circuit
 
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the result does comes different by two methods
 
umed9 said:
in most of the books i have seen that while finding an impedance for an parallel RLC circuit first they find the individual admittance of each of the element the after summation of these they take reciprocal to find the impedance
why is it done like that can't we find the impedance in a normal way of finding resistance in parallel circuit

umed9 said:
the result does comes different by two methods

Can you show us how you get two different results using the two different methods? I would not expect that...
 
If you add the admittance and convert to impedance you will get the same result as working out the impedance of 3 parallel elements. Just do the math both ways with Z1, Z2, and Z3 and if they don't agree, do it again until you find the math error. 1/((1/Z1) + (1/Z2) + (1/Z3)) = Zt and the long form for Z1||Z2||Z3 = Zt where Z1||Z2 is (Z1*Z2)/(Z1+Z2)
 

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