Finding Intersection of Curves: sin(x) and 2|x|/pi

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SUMMARY

The discussion focuses on calculating the area of the finite region enclosed by the curves defined by the equations y = 2|x|/π and y = sin(x). The integral representing the area is sin(x) - (2x/π). The primary challenge discussed is finding the intersection points of the two curves, specifically solving the equation sin(x) = (2x/π). The user identifies x = 0, π/2, and -π/2 as intersection points but seeks a methodical approach to determine these points rather than relying on observation.

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Calculate the are of the finite region enclosed by the curves ## y = \dfrac{2|x|}{\pi} ## and ## y = sin(x) ##

I understand that the integral is ## sin(x) - \dfrac{2x}{\pi} ## however I'm having troubles finding where they intersect, I can only find x= 0, how do I solve ## sin(x) = \dfrac{2x}{\pi} ## ? I can see by observation that 0, pi/2, -pi/2 work but is there a method to find these instead of observation?
 
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hi phospho! :smile:
phospho said:
I can see by observation that 0, pi/2, -pi/2 work but is there a method to find these instead of observation?

sorry, not without a computer or special tables :redface:

but what's wrong with observation? :wink:
 
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