Finding Length of Curve Represented by Parametric Equations

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SUMMARY

This discussion focuses on calculating the length of a curve defined by parametric equations, specifically x = g(t) and y = f(t). The integral for the curve length is established as ∫√((f'(t))² + (g'(t))²) dt. A key challenge is determining whether the curve overlaps itself within a specified interval [a, b]. The solution involves analyzing the graphs of x = g(t) and y = f(t) to identify any repeating values, ensuring that the integration only accounts for unique traversals of the curve.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of calculus, specifically integration techniques
  • Familiarity with derivatives and their applications
  • Graphing skills to analyze function behavior
NEXT STEPS
  • Study the concept of parametric curves in detail
  • Learn about the application of the Fundamental Theorem of Calculus in parametric equations
  • Explore techniques for identifying curve intersections and overlaps
  • Investigate numerical methods for approximating integrals of parametric equations
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Mathematicians, engineering students, and anyone involved in computational geometry or curve analysis will benefit from this discussion.

Miike012
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I am having difficulty finding the length of the curve represented by parametric equations. The difficulty comes from not knowing how to determine if the curve transverses once, twice,... in a given interval.

The only solution I can think of is (say x = g(t) and y = f(t) and y = F(x) on interval [a,b] )
Look at graph x = g(t) and determine on the interval [a,b] if there are any values of x that repeat
If so then the graph y = F(x) on [a,b] may transverse more than once,
next look at the graph y = f(x) and determine if and y values repeat.

Then from these values one should be able to determine if the graph y =F(x) overlaps its self... but I know there must be a better method...
Help please.
 
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If the curve is given by x= g(t) and y= f(t) then dx/dt= f'(t) and dy/dt= g'(t) so dx= f'(t)dt and dy= g'(t)dt. The integral for curve length is
[tex]\int \sqrt{(dx)^2+ (dy)^2}= \int \sqrt{(f'(t)dt)^2+ (g'(t)dt)^2}= \int\sqrt{(f'(t))^2+ (g'(t))^2}dt[/tex]

If the graph "overlaps itself" you only want to integrate over values of t that go over the path once. Choose some convenient point, [itex](x_0, y_0)[/itex], and find succesive solutions to [itex]f(t)= x_0[/itex], [itex]g(t)= y_0[/itex].
 

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