- #1

fran1942

- 80

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Hello, I am tying to use l'Hopital's rule to solve this limit:

{e^(5+h)-e^5} / h

limit h tending towards 0

Using l'Hopitals rule I differentiate both numerator and denominator to get:

e^(5+h)-e^5 / 1

THen plugging 0 back in I get 0/1 which would give me a limit of 0 ?

But I think the limit should actually be e^5.

Can someone see where I have gone wrong ?

Thanks kindly

{e^(5+h)-e^5} / h

limit h tending towards 0

Using l'Hopitals rule I differentiate both numerator and denominator to get:

e^(5+h)-e^5 / 1

THen plugging 0 back in I get 0/1 which would give me a limit of 0 ?

But I think the limit should actually be e^5.

Can someone see where I have gone wrong ?

Thanks kindly

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