Finding Local Max and Min values and saddle in mult. Calculu

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To find local maximum and minimum values and saddle points for the function f(x,y) = x^2 + xy + y^2 + y, the first step is to compute the partial derivatives, yielding fx = 2x + y and fy = x + 2y + 1. Setting these partial derivatives equal to zero helps identify critical points. Once the critical points are determined, they must be tested to classify them as local maxima, minima, or saddle points. This process is essential for analyzing the behavior of the function in multivariable calculus.
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Homework Statement


Find the local maximum and minimum values and saddle points of the function
f(x,y) = x^2 + xy + y^2 + y

Homework Equations


Local max/min
critical points
saddle

The Attempt at a Solution


1) partial derivative: fx = 2x+y fy = x+2y+1

from here, I'm a little confuse on what should i do to find the critical point in order to solve for the local max/min.
 
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Physicsnoob90 said:

Homework Statement


Find the local maximum and minimum values and saddle points of the function
f(x,y) = x^2 + xy + y^2 + y

Homework Equations


Local max/min
critical points
saddle

The Attempt at a Solution


1) partial derivative: fx = 2x+y fy = x+2y+1

from here, I'm a little confuse on what should i do to find the critical point in order to solve for the local max/min.

Set the two partials equal to zero and solve for the critical point ##(a,b)##. Then test it.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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