Finding magnitude and direction of a rocket

[CandyApples]

Homework Statement

A model rocket has been fired with V₀=50m/s at 35 degrees above horizontal. Find magnitude and direction at t=4s.

Homework Equations

V = V₀+at, displacement = v₀t + .5at²

The Attempt at a Solution

I have successfully found the magnitude by setting V_x= 50*cos35 and V_y = 50sin35 -4g then taking the square root of each direction squared to find the magnitude is equal to 42.289 m/s. I am having trouble now, figuring out what to do to figure out the direction. I have calculated displacement of x to be 163.83m and displacement of y to be 36.32m by using the displacement equation. Any hints on how to find the angle? I thought inverse tangent of y/x would give me the correct displacement, however it did not.

 

[LeonhardEuler]

Be careful. "Find the magnitude and direction" is ambiguous, but based on the fact you got the correct answer for the magnitude by taking the magnitude of the velocity, I assume the question is "Find the magnitude and direction of the velocity", not "Find the magnitude of the velocity and the direction of the displacement", which is what you solved.

 

[Jebus_Chris]

If you draw a triangle you will see that Vx and Vy form a right triangle with V. You can use trig(tan) to find the angle.