Consider three charges arranged as shown.
What is the magnitude of the electric field
strength at a point 2.7 cm to the left of the
middle charge? The value of the Coulomb
constant is 8.98755 × 109 N · m2/C2 . Answer
in units of N/C.
I'm truly lost. I've been looking over some other places, trying to put things together, but nothing is becoming clear to me... How do the positive and negative charges affect each other? For example if I have 2 equal positive charges, the electric field should be 0 right? How do I determine it if it is 1 positive and 1 negative charge? (Both the same value -1 and +1)
The Attempt at a Solution
I was looking at some similar problems.
E1 = 8.98755e9 x 5.6e-6 / .064^2 = 1.228766602e7. I got that distance by finding the total distance between the point 2.7 cm to the left. So 3.7 + 2.7 = 6.4. That could be very wrong, I'm not sure.
E2 = 8.98755e9 x 3.2e-6 / .047^2 = 1.301953825e7
E3 = 8.98755e9 x -1.8e-6 / .017^2 = -5.597782007
Then i just decided to add all three of those together... As I said I'm really lost, and I'm quite sure none of what I did is correct. Any help?
Edit : Sorry... I inserted a picture to show the problem.