Finding maximum/minimum values?

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SUMMARY

The maximum and minimum values of the function y = 28(1.21)^x on the interval 0 ≤ x ≤ 12 are determined by the properties of exponential functions. The minimum value occurs at the left endpoint, where y = 28 when x = 0. The maximum value is found at the right endpoint, calculated as y = 28(1.21)^12. Therefore, the minimum value is 28 and the maximum value is approximately 109.75.

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eleventhxhour
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What are the maximum/minimum values for y = 28(1.21)^x on the interval 0 $\le$ x $\le$ 12?

I think that the minimum value might be 28 because y = 28 when x = 0 but I don't know how to find the maximum value. Could someone help/explain? Thanks.
 
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An exponential function, whose base $b$ is greater than 1, of the form:

$$y=kb^x$$ where $0<k$ will be monotonically increasing on any interval within the domain, which is all reals. Thus, the function will have it's minimum at the left-endpoint and its maximum at the right end-point.
 

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