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Two charges are placed on the x axis. One charge (q1 = +16.5 µC) is at x1 = +3.0 cm and the other (q2 = -19 µC) is at x2 = +9.0 cm. Find the net electric field (magnitude and direction) at the following locations.

(a) x = 0 cm

magnitude= ? N/C

direction= ?

(b) x = +6.0 cm

magnitude= ? N/C

direction= ?

I set E1=E2

[K(+16.5*10^-6)]/X^2 = [K(-19*10^-6)]/(X+.06)^2

After canceling everything out I get 16.5(X+.06)^2 = 19X^2

Then solving for X I get .8219 and -.0289

I am not sure what I am doing wrong. The (10^-6) should cancel out right?

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# Homework Help: Finding net electric field at different locations

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