Finding percentage and absolute uncertainties

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SUMMARY

The discussion focuses on calculating percentage and absolute uncertainties in the context of Young's modulus. Key values provided include 2.0×10-7, 40 N, 0.05, and 4×109 Pa. The formula for Young's modulus is confirmed as (Force ÷ Area) ÷ (Extension ÷ Load). Participants emphasize the importance of considering relative errors in measurements and suggest using quadrature for independent errors. A method for estimating extreme values for extension is also proposed for uncertainty analysis.

PREREQUISITES
  • Understanding of Young's modulus and its formula
  • Familiarity with relative and absolute error concepts
  • Basic knowledge of error propagation techniques
  • Ability to perform calculations involving quadrature for independent errors
NEXT STEPS
  • Research the concept of relative error in measurements
  • Learn about error propagation in physical calculations
  • Study the application of quadrature in uncertainty analysis
  • Explore methods for calculating extreme values in experimental data
USEFUL FOR

Students and professionals in physics and engineering, particularly those involved in experimental measurements and materials science, will benefit from this discussion on uncertainty calculations related to Young's modulus.

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Homework Statement
Find the percentage and absolute uncertainities in the young modulus if the uncertainty in the extension is ±1 mm.
Relevant Equations
Young modulus= Stress ÷ Strain
the answers to other parts of the question:

a, 2.0×10-⁷
b, 40 N
c, O.O5
d, 4×10⁹Pa
I Really don't understand how to solve the e part
I Know that Young modulus= (Force÷Area)÷(Extension÷Load)
kindly guide how to solve this question.
IMG_20230113_115541.jpg
 
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This is somewhat undetermined, because you have no information on the uncertainty of the other factors. My guess is that you are supposed to ignore them.

The simplest form (even simpler than this) says
relative error in product or quotient due to one of the factors is equal to relative error in that factor. So if ##f = A B## and A has an relative error of 0.2 and B has a relative error of negligible magnitude, then the relative error in ##f## is also 0.2

idem if ##f=A/B##.

If the error in ##B## can not be ignored (and is independent of the error in A) then the errors should be added in quadrature (see the link).

Does this help ?

##\ ##
 
If you have not been taught the formulae @BvU quotes, an obvious way is to calculate the extreme values that the extension might really be and see what values those would give for the modulus.
 
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