Finding R_Thevenin involving dependent source

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
Bishamonten
Messages
17
Reaction score
1

Homework Statement


upload_2017-5-14_19-23-33.png


Homework Equations



Impedances:

Inductor = jωL; Capacitor = 1/jωC

The Attempt at a Solution


I attempted to excite the circuit with an Io = 1A source, and then from Zc = 1/jX2 justify Vx = (1)(Zc)

Thus, substituting our found Vx and then doing a source transformation, we find our V = g(Vx)(jX1), and thus, our RTh = V/Io, which is not correct. The correct answer is #1 in the image.[/B]
 
Physics news on Phys.org
Bishamonten said:
I attempted to excite the circuit with an Io = 1A source, and then from Zc = 1/jX2 justify Vx = (1)(Zc)

Thus, substituting our found Vx and then doing a source transformation, we find our V = g(Vx)(jX1), and thus, our RTh = V/Io, which is not correct. The correct answer is #1 in the image.
Exciting the circuit with a current source is good. I think that where you've gone wrong is after your source transformation.
The voltage source from that transformation is not the potential that appears across ab. There are now two components between that source and the "a" terminal, the impedance X1 associated with the transformed source and the capacitor's X2.