Finding R_Thevenin involving dependent source

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SUMMARY

The discussion focuses on finding the Thevenin resistance (R_Thevenin) in a circuit with a dependent source. The user attempted to solve the problem by exciting the circuit with a 1A current source and calculating the voltage across the capacitor using Zc = 1/jX2. However, the user miscalculated the voltage after performing a source transformation, leading to an incorrect R_Thevenin value. The correct approach involves recognizing the additional impedance components between the transformed source and the terminals.

PREREQUISITES
  • Understanding of Thevenin's theorem
  • Knowledge of impedance calculations for inductors and capacitors
  • Familiarity with source transformations in circuit analysis
  • Basic concepts of dependent sources in electrical circuits
NEXT STEPS
  • Study Thevenin's theorem applications in circuits with dependent sources
  • Learn about impedance calculations for complex circuits
  • Explore source transformation techniques in circuit analysis
  • Review examples of circuits with multiple impedance components
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing circuits with dependent sources and Thevenin equivalents.

Bishamonten
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Homework Statement


upload_2017-5-14_19-23-33.png


Homework Equations



Impedances:

Inductor = jωL; Capacitor = 1/jωC

The Attempt at a Solution


I attempted to excite the circuit with an Io = 1A source, and then from Zc = 1/jX2 justify Vx = (1)(Zc)

Thus, substituting our found Vx and then doing a source transformation, we find our V = g(Vx)(jX1), and thus, our RTh = V/Io, which is not correct. The correct answer is #1 in the image.[/B]
 
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Bishamonten said:
I attempted to excite the circuit with an Io = 1A source, and then from Zc = 1/jX2 justify Vx = (1)(Zc)

Thus, substituting our found Vx and then doing a source transformation, we find our V = g(Vx)(jX1), and thus, our RTh = V/Io, which is not correct. The correct answer is #1 in the image.
Exciting the circuit with a current source is good. I think that where you've gone wrong is after your source transformation.
The voltage source from that transformation is not the potential that appears across ab. There are now two components between that source and the "a" terminal, the impedance X1 associated with the transformed source and the capacitor's X2.
 

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