Finding relative coordinates of a vector

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Homework Help Overview

The original poster is attempting to find the coordinates of a vector [7, 4, 1] relative to three given vectors: [-1, 2, -9], [1, 5, 1], and [47, -8, -7]. The context involves linear combinations of vectors.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of setting up an augmented matrix to find the coefficients of the linear combination. There is a question regarding the appropriateness of the number 47 in the third vector, with some participants confirming its inclusion based on prior context.

Discussion Status

The discussion is ongoing, with participants confirming the setup of the augmented matrix and discussing the implications of a potential mistake in calculations. Some guidance has been offered regarding the method, but there is no explicit consensus on the correctness of the values obtained.

Contextual Notes

There is mention of a previous problem involving the cross product that led to the inclusion of the vector with the number 47, which may influence the current setup and assumptions.

war485
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Homework Statement



I'm trying to find the coordinates of a vector [ 7 4 1 ] relative to these three vectors:
[ -1 2 -9 ] , [ 1 5 1 ] , [ 47 -8 -7 ]

Homework Equations



none

The Attempt at a Solution



Do I get all these vectors into an augumented matrix?
like:
[ -1 1 47 | 7 ]
[ 2 5 -8 | 4 ]
[ -9 1 -7 | 1 ]
and then row reduce completely? I got very awkward numbers and just wanted to make sure I'm using the correct method.
 
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I take it that "relative to these three vectors" means write it as a linear combination of those vectors. What you want are three numbers, a, b, c such that
a<-1, 2, 9>+ b<1, 5, 1>+ c<47, -8, -7>= <7, 4, 1>. Looking at x, y, and z components separately that means -a+ b+ 47c= 7, 2a+ 5b- 8c= 4, 9a+ b- 7c= 1 which gives exactly the augmented matrix you have.

Are you sure about that "47"? That number looks out of place.
 
yes that 47 must be there because it was part of another question where I had to find a third vector orthogonal to the other two (involving the cross product) and I'm confident about that.

If you say that my setup is right, then my more awkward numbers must be right.
I got
a = -4/43
b = 28/27
c = 145/1161
 
oups, I made a mistake and it'll affect my a b c values. But thanks for confirming my method Ivy.
 
Last edited:

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