The discussion revolves around understanding the calculation of shearing forces and moments in a beam under various loads. Participants are examining specific points along the beam and questioning the reasoning behind the values of shearing forces and moments at those points, as well as the methodology used in the calculations.
Participants express differing views on the calculations and interpretations of shearing forces and moments, indicating that multiple competing perspectives remain unresolved. There is no consensus on the correct approach to the problem.
Participants have not fully resolved the assumptions regarding the calculations and the definitions of terms used in the discussion. The discussion includes various interpretations of the shearing force and moment diagrams, which may depend on specific definitions and contexts.
one more thing , why at x = 6 , the shearing force is still 49kN as in the calculation ? why shouldn't it be = 0 ?David Lewis said:
Because the reaction RA is located at x = 2. As you move along the beam from left to right, the shear force has a sudden jump from V = -40 kN to V = 89 kN, as the reaction RA = 129 kN is added.foo9008 said:
Why should the shear be zero at x = 6?foo9008 said:
sudden jump means there are 2 values of RA at x =2 ? why ?SteamKing said:
Because they are each integrals. The shear force is the integral of the load curve w.r.t. length, and the bending moment is the integral of the shear curve, also w.r.t. length.foo9008 said:
No, there is only one value of RA, namely RA = 129 kN.foo9008 said:
