Finding Solutions for Complex Numbers: z^2 = 1+2i

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
static
Messages
3
Reaction score
0

Homework Statement



Determine all solutions of z^2 = 1+2i in the form z=a+bi, where a and b are real numbers.For this question numerical evaluation is not required. I just don't know how to start.:mad:
any clue?
thanks!
 
Physics news on Phys.org
Reformulate 1+2i in the exponential form
 
static said:
Determine all solutions of z^2 = 1+2i in the form z=a+bi, where a and b are real numbers.

For this question numerical evaluation is not required. I just don't know how to start.:mad:
It seems that even if you don't have a good idea how to arrive at an answer, you have an obvious starting path: plug the answer form "z=a+bi" into the equation you're trying to solve. It may, or it may not, lead to something that works, but at least it's something to try.
 
Yep, your solution is z=a+bi, just plug it in the equation, and solve the equation. You will come up with two equations (which are actually Vieta's formulas), and you can create quadratic equation and solve for a and b.

Regards.