A car of weight 1920 N operating at a rate of
107 kW develops a maximum speed of 41 m/s
on a level, horizontal road.
Assuming that the resistive force (due to
friction and air resistance) remains constant,
what is the car’s maximum speed on an incline
of 1 in 20; i.e., if θ is the angle of the incline
with the horizontal, sin θ = 1/20 ?
Answer in units of m/s.
This is the equation that i believe we have to use.
P=F x V
The Attempt at a Solution
So we have 107 kW which i assume i have to change to 107000 W.
Then we do 107000= F x 41m/s
i got F=2609.7560
Then for the incline plane the Watts should be the same but im not sure what to do with the angle of the incline. Should I tack it on to the force? sin θ = 1/20 I guess that means the hypotenuse is 20 and the height of the incline is 1. And im not sure where the weight of the car comes into play.