Finding spring constant by comparing to another spring

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SUMMARY

The discussion focuses on calculating the spring constant of a second spring based on the known spring constant of the first spring, which is 186 N/m. The objects attached to both springs oscillate with the same maximum velocity, but the amplitude of the first spring's motion is three times that of the second spring. The correct approach involves using the relationship between amplitude and spring constant in simple harmonic motion, leading to the conclusion that the spring constant of spring 2 is 20.6 N/m, although the initial calculation was incorrect due to a mix-up in the springs.

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rasputin66
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Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring constant of spring 1 is 186 N/m. The motion of the object on spring 1 has 3 times the amplitude as the motion of the object on spring 2. The magnitude of the maximum velocity is the same in each case. Find the spring constant of spring 2.

My work...

Aw=Aw
A(sqrt of k/m) = A(sqrt k/m)
(sqrt of 186) = 3 (sqrt of k)
(sqrt of 186)/3 = (sqrt of k)
[(sqrt of 186)/3] ^2 = k
I got 20.6 but this is wrong, Please help!
 
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You're on the right track. You just got the springs mixed up. Do it over more carefully.
 
OH MY GOD. What is wrong with me??

Thanks!
 

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