Finding tangents, given (x,y) information

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The discussion focuses on finding the derivatives of functions defined as h(x) using given values for f and g at x=2. Specifically, participants calculate h′(2) for four different functions: h(x)=f(x)g(x), h(x)=g(x)/(1+f(x)), h(x)=x²/f(x), and h(x)=g(x)/x². The first derivative for h(x)=f(x)g(x) is derived using the product rule, resulting in h'(x) = f'(x)g(x) + f(x)g'(x). The values f(2)=-3, g(2)=3, f′(2)=-3, and g′(2)=7 are then substituted to find the specific derivative at x=2.

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musad
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Stuck on another calculus question and not sure where to begin:

For each h(x) defined below, find h′(2), given that f(2)=−3,g(2)=3,f′(2)=−3 and g′(2)=7.
a) h(x)=f(x)g(x)

b) h(x)=g(x)/1+f(x)

c) h(x)=x^2/f(x)

d) h(x)=g(x)/x^2


Thanks for all your help. Sorry for bombarding but these are the last few that I am stuck on.
 
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Question a).
Step 1: Calculate the first derivative
$$h'(x) = [f(x)g(x)]' = f'(x)g(x)+f(x)g'(x)$$
Step 2: Plug in the values $f(2),f'(2),g(2)$ and $g'(2)$.

The others are similar.
 

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