Finding Tension and Acceleration on Frictionless Surfaces

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SUMMARY

The discussion focuses on calculating the tension and acceleration in a system involving three masses: two hanging (100g and 200g) and one on a frictionless surface (200g). The equations derived from free body diagrams include Fnet = ma, with specific attention to the relationships between tensions T1 and T2 across the pulleys. The key conclusion is that the tensions in ideal strings are equal on both sides of the pulleys, and consistent sign conventions must be maintained when solving the equations for T1, T2, and acceleration (a).

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of free body diagrams (FBD) for analyzing forces
  • Familiarity with the concept of tension in strings and pulleys
  • Basic principles of gravity (g = 9.8 m/s²)
NEXT STEPS
  • Study the principles of tension in ideal strings and pulleys
  • Learn how to construct and analyze free body diagrams for multi-mass systems
  • Explore the effects of friction on tension and acceleration in similar systems
  • Practice solving systems of equations involving multiple unknowns in physics problems
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Students studying physics, particularly those focused on mechanics, as well as educators looking for examples of tension and acceleration calculations in frictionless systems.

m.piet
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Homework Statement


For the following system 1) Find the tension in the string
2) find the acceleration of each of the masses

The diagram of the system looks like this

...O-----|200g|-----O
...|.\___|____|___/.|
__|__....__|__ ( . ) are placeholders to make the diagram look accurate
|100g|...|200g|

Basically a mass of 200g on a frictionless surface attached to 2 other masses (100g and 200g) hanging over the edge of the surface with a string on frictionless pulleys. String has no mass and can not expand. Gravity is 9.8 m/s^2.

The attempt at a solution
First off I converted all my masses to Kg
I have numbered each mass from left to right from 1-3 and have drawn free body diagrams for them. These are the equations I got for each

1)
Fnet = ma
Fnet = T-Fg
Fg= mg
ma = T-Fg
(0.1)a = T-0.98
So: T = 0.1a + 0.98
a = (T- 0.98) / 0.1


2)
Fnet = ma
Fnet = T1 - T2 (T1 and T2 are the tensions to the 1st and 3rd masses, respectively)
T1 - T2 = ma
T1 - T2 = 0.2a

3)
Fnet = ma
Fnet = T-Fg
Fg = mg
ma= T-Fg
0.2a = T-1.96
So: T = 0.2a + 1.96
a = (T-1.96) / 0.2



I am stuck at whether the mass that is on the surface will even matter to the acceleration and tension of the system because the surface is frictionless so would that mean I could solve as if there is no mass there? Or would I have to isolate the system into 2 systems, 1,2 and 2,3, then solve for each tension and acceleration and go from there?
 
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You're doing OK except for a couple of things. You should first note that tensions in ideal strings wrapped around ideal pulleys are the same on both sides of the pulley. So what you call T in your FBD of mass 1, you should call T1; and what you call T in your FBD of mass 3 you should call T2. Secondly, be consistent with your plus and minus signs; since you have assumed that the lighter hanging mass is moving upward, then mass 3 must be moving downward, and mass 2 must be moving to the right. Then just solve the 3 equations for the 3 unknowns T1, T2, and a.
 

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