Finding the -3dB corner frequency of the circuit.

  • Context: Engineering 
  • Thread starter Thread starter tarmon.gaidon
  • Start date Start date
  • Tags Tags
    Circuit Frequency
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
tarmon.gaidon
Messages
30
Reaction score
0
Hey Everyone,

The circuit I am interested in is attached. I was just looking for a little input to help me start this problem. As the title states I am just looking to find the -3dB frequency of this circuit.

Point me in the right direction :)
 

Attachments

  • Untitled.png
    Untitled.png
    4.9 KB · Views: 551
Physics news on Phys.org
Write the equation for the output voltage as a function of frequency. Then using that equation, find the frequency that makes the output X times lower than the input where X is given by the equation below.

3dB = 20 Log10(X).
 
The circuit begins with a voltage divider that cuts Vsource in half. That's already more than 3dB down (1/√2 ≈ 0.7071). Perhaps you're looking for where it's 3db down compared to a DC input voltage?