Finding the absolute maximum and absolute minimum

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Homework Help Overview

The problem involves finding the absolute maximum and minimum of the function f(t) = t + cot(t/2) over the interval [π/4, 7π/4].

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the process of finding the derivative of the function and express doubts about the correctness of their calculations. There is a focus on identifying critical points within the specified interval.

Discussion Status

Some participants have made progress in calculating the derivative and are exploring how to find critical points. There is an ongoing dialogue about the next steps and the implications of their findings.

Contextual Notes

Participants are working within the constraints of the problem and are questioning their assumptions about the derivative and critical points. There is mention of needing to graph functions to aid in understanding the solutions.

meeklobraca
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Homework Statement



Find the absolute max and min of

f(t)=t + cot(t/2) on [pi/4, 7pi/4]

Homework Equations





The Attempt at a Solution



I have attempted to find the derivative which I believe is

1 - csc^2 (t/2) * (t/2) which I can simplify down to cot^2 (t/2) * (t/2)

Even if that is correct, which I am doubtful of, where do I go from here?

Thank You!
 
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Why do you think the derivative of t-cot(t/2) is 1-(csc^(t/2))*(t/2)? Better fix that before you try to proceed.
 
Okay I've found the derivative of t + cot (t/2) to be

1 - csc^2(t/2) * 1/2
 
meeklobraca said:
Okay I've found the derivative of t + cot (t/2) to be

1 - csc^2(t/2) * 1/2

That's much better. So do you have any critical points on [pi/4, 7pi/4]?
 
Here in lies the problem Dick. Where do you go from here?

im at sqrt 2 = csc (t/2) from which I've turned into sqrt 2 = 1/sin (t/2)
 
That's pretty good progress. Actually possibilities are at sin(t/2)=+/-1/sqrt(2). Can you draw a graph of sin(x) and tell me where sin(x)=+/-1/sqrt(2)? Then put t/2=x. I happen to know sin(pi/4)=1/sqrt(2).
 

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