Finding the Acceleration of Gravity from these Dropped Ball Experiments

[Bobb]

Homework Statement

Basically we did a lab where we dropped a ball and recorded the times then we created 3 graphs. Height vs t, height vs t^2. and sqrt of height vs. t. Where I'm confused is they want us to two 2 values of g from the slopes of the height vs t^2. and sqrt of height vs. t graphs. I thought the slope for height vs t^2 was already acceleration how would we find g from these?

Relevant Equations

X = Xo +Vot + 1/2at^2

0 = Yo + 0 -1/2gt^2

Did not know where to start so I tried A= v/t to find velocity then plug into equation to find g, but i got a huge g.

 

[Chestermiller]

Homework Statement: Basically we did a lab where we dropped a ball and recorded the times then we created 3 graphs. Height vs t, height vs t^2. and sqrt of height vs. t. Where I'm confused is they want us to two 2 values of g from the slopes of the height vs t^2. and sqrt of height vs. t graphs. I thought the slope for height vs t^2 was already acceleration how would we find g from these?
Homework Equations: X = Xo +volt + 1/2at^2

0 = Yo + 0 -1/2gt^2

Did not know where to start so I tried A= v/t to find velocity then plug into equation to find g, but i got a huge g.

Let’s see your graph of height vs t^2

 

[Bobb]

Second one, teacher wanted it to be in y= mx+b form

 

[Chestermiller]

Second one, teacher wanted it to be in y= mx+b form

How can the height be increasing with time?

 

[Orodruin]

How can the height be increasing with time?

If you drop something from higher up it takes longer to get to the ground.

0 = Yo + 0 -1/2gt^2

So what does this tell you about Yo as a function of t^2? If you let t^2 = s, you are asked to find g by computing the slope of the function Yo(s).

 

[Chestermiller]

If you drop something from higher up it takes longer to get to the ground.

Ah. I was confused. I though he was measuring the distance fallen in a single drop as a function of time.