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Finding the area between curves

  1. Dec 8, 2007 #1
    1. The problem statement, all variables and given/known data

    y = x^5 - 2ln(x+5)

    and

    y = x^3 - 2ln(x+5)


    2. Relevant equations



    3. The attempt at a solution

    i put it ont he calculator but i honestly dont even no where the spot that i amtrying to find the area for is
     
  2. jcsd
  3. Dec 8, 2007 #2

    rock.freak667

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    Homework Helper

    well find where they intersect and you will find the limits of the required integral
     
  4. Dec 8, 2007 #3
    they intersect at x = 9.24???
     
  5. Dec 8, 2007 #4
    They also pretty clearly intersect at 0.
     
  6. Dec 8, 2007 #5
    ok so now how do i get started with that
     
  7. Dec 8, 2007 #6
    Actually, I wasn't paying attention. How did you get 9.24 as an intersection point? They intersect at x = 0 and x = 1. Those are the limits of integration that are desired I imagine.
     
  8. Dec 9, 2007 #7
    yea i dont even no where the 9.24 came from.. so i do it from x=0 to x=1 and what is the top and bottom values??
     
  9. Dec 9, 2007 #8

    Defennder

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    Homework Helper

    Uh, I didn't sketch the graph when I did this, but isn't x=-1 also a possible intersection point?
     
  10. Dec 9, 2007 #9

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    One of the very first things you should have learned is that two curves intersect where the same x-value gives the same y-value.

    The graphs of y = x^5 - 2ln(x+5) and y = x^3 - 2ln(x+5) intersect where
    y= x^5- 2ln(x+5)= x^3- 2ln(x+5). Can you solve that equation?
     
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