Finding the area between curves

[rayray19]

Homework Statement

y = x^5 - 2ln(x+5)

and

y = x^3 - 2ln(x+5)

Homework Equations

The Attempt at a Solution

i put it ont he calculator but i honestly don't even no where the spot that i amtrying to find the area for is

 

[rock.freak667]

well find where they intersect and you will find the limits of the required integral

 

[rayray19]

they intersect at x = 9.24?

 

[Mystic998]

They also pretty clearly intersect at 0.

 

[rayray19]

ok so now how do i get started with that

 

[Mystic998]

Actually, I wasn't paying attention. How did you get 9.24 as an intersection point? They intersect at x = 0 and x = 1. Those are the limits of integration that are desired I imagine.

 

[rayray19]

yea i don't even no where the 9.24 came from.. so i do it from x=0 to x=1 and what is the top and bottom values??

 

[Defennder]

Uh, I didn't sketch the graph when I did this, but isn't x=-1 also a possible intersection point?

 

[HallsofIvy]

One of the very first things you should have learned is that two curves intersect where the same x-value gives the same y-value.

The graphs of y = x^5 - 2ln(x+5) and y = x^3 - 2ln(x+5) intersect where
y= x^5- 2ln(x+5)= x^3- 2ln(x+5). Can you solve that equation?