Finding the Center of Area of Remaining Part After Cutting Out a Quarter Circle

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SUMMARY

The discussion focuses on finding the centroid of the remaining area after a quarter circle is cut from a square of dimensions (a x a) with radius r. The coordinate for the removed quarter circle is identified as a - 4r/3π. To determine the centroid of the remaining area, the relationship between the center of mass and the area of the shapes is utilized, specifically using the equation m1R1 + m2R2 = 0, where m represents mass and R represents the position vector. The mass of the quarter circle is treated as negative, allowing for the calculation of the centroid of the remaining area.

PREREQUISITES
  • Understanding of centroid and center of mass concepts
  • Familiarity with basic geometry, specifically squares and circles
  • Knowledge of calculus for area calculations
  • Ability to apply equations of equilibrium in physics
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  • Study the derivation of the centroid formula for composite shapes
  • Learn about the properties of centroids in two-dimensional shapes
  • Explore the application of integration in finding areas and centroids
  • Investigate the concept of negative mass in physics and its implications
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Mathematicians, physics students, and engineers interested in geometric properties and centroid calculations, particularly in applications involving composite shapes.

teng125
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a square with dimensions (a x a),a quater circle is cut out which has the radius r.Find the center of area of the remaining part.
i found the coordinate for the removed quater circle which is a-4r/3pi ,
but i don't know how to find the cenroid of the remaining part.


anybody pls help

thanx
 
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teng125 said:
a square with dimensions (a x a),a quater circle is cut out which has the radius r.Find the center of area of the remaining part.
i found the coordinate for the removed quater circle which is a-4r/3pi ,
but i don't know how to find the cenroid of the remaining part.
The centre of area is the same as the centre of mass of a sheet of uniform thickness and density.

The centre of mass of two objects is the point at which the products of the distance to the centre of mass x mass of each object sum to zero.

m_1R_1 + m_2R_2 = 0

The mass of the object is its area x mass/area (m=\sigma A)

Think of the sheet as a whole sheet superimposed with a quarter circle of negative mass. The centre of mass of the full sheet is its centre. If you can work out the centre of area or mass of the quarter circle, then it is just a simple matter of using the above equation.

AM
 

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