Finding the center of mass of an incomplete circle

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Homework Help Overview

The problem involves finding the x coordinate of the center of mass of a homogeneous rod shaped into a circular arc with a specified radius. The arc is defined by certain angular limits, which are under scrutiny.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration process used to find mass and moments, with one participant questioning the limits of integration. There is also a mention of discrepancies in expected results based on different angular limits.

Discussion Status

Some participants have provided guidance on unit presentation and significant figures. There is ongoing exploration of the correct limits for integration, with multiple interpretations of the problem being considered.

Contextual Notes

Participants note potential errors in the problem statement regarding the angular limits and the expected result, suggesting that the problem may have been altered from a previous version.

Jbray
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Homework Statement



Locate the x coordinate of the center of mass of the homogeneous rod bent into the shape of a circular arc. Take r = 170 .

The arc goes from (-5/6) to (5/6)pi (counterclockwise). It has a radius of 170mm.

Homework Equations



x=rcosθ, y=rsinθ, dL=r*dθ

The Attempt at a Solution



I found "M" by integrating "170 dθ" from (-5/6)pi to (5/6)pi. This gave me 890.12mm.I found "My" by integrating "170 (cosθ) 170 dθ" from (-5/6)pi to (5/6)pi. This gave me 170^2 or 28900mm.

I used My/M to find the x coordinate of the center of mass as 28900/890.12 or 32.468mm. However this is incorrect.
 
Last edited:
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The solution looks good, but you miss the unit, and try to give the result with three significant digits.

ehild
 
I updated the units. I also found out that the answer is supposed to be 70.3mm but I still can't figure out how to get that.
 
Are the limits -5/6 and 5/6pi, or -5/6pi and 5/6pi? But even then, the result is different from that 70 mm. The given results happen to be wrong quite often.

ehild
 
Jbray said:
the answer is supposed to be 70.3mm
That would be the answer if the angle were -2π/3 to +2π/3.
 
haruspex said:
That would be the answer if the angle were -2π/3 to +2π/3.

You are a genius! So they took over the solution from an old version of the problem, while changing the limits in the problem text. :biggrin:

ehild
 

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