Hi guys! Just a little confused on the solution provided. 1. The problem statement, all variables and given/known data A crate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.50 m/s. The pulling force is 100 N parallel to the incline, which makes an angle of 20.0° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 5.00 m. (d) What is the change in kinetic energy of the crate? 2. Relevant equations Change in word done = Fs - mgsin[itex]\Theta[/itex]s - friction I understand this part but I want to know why the solution key takes this change as the change in kinetic energy itself. Isn't there a gain in G.P.E. as well? Thanks for the help!